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Cheatsheet: Why area equals slope

Why does ∫_a^b f dx = F(b) - F(a)? Why does an area equal a difference of values of a related function? Area and slope look unrelated. They are not.

A(x) = ∫_a^x f(t) dt (area under f, from fixed a to moving x)

Slide the right end by dx. The new area is a thin sliver: width dx, height f(x).

A(x + dx) - A(x) ≈ f(x) · dx
[ A(x+dx) - A(x) ] / dx ≈ f(x)
as dx -> 0: A'(x) = f(x)

The derivative of the area function is the original curve.

A' = f means A is an antiderivative of f. Any antiderivative F differs by a constant (which cancels), so:

F(b) - F(a) = A(b) - A(a) = ∫_a^b f(x) dx

Integration and differentiation are inverse operations because the slope of an accumulated area is the thing being accumulated.

Worked examples (A’(x) = f(x) every time)

Section titled “Worked examples (A’(x) = f(x) every time)”
farea function A(x)A'(x)
x^2x^3/3x^2
e^xe^x - 1e^x
2πr (circle)πR^22πR

The circle case is L1’s observation, now proved general.

A bucket under a tap: the rate the water level rises equals the tap’s flow at that moment. Water level = the integral; flow = the function; fill-rate = flow is A'(x) = f(x). The rate a total accumulates is the thing accumulating.

The PDF-and-CDF pairing: the cumulative distribution F(x) = ∫ f(t) dt has derivative F'(x) = f(x), the density. Every PDF/CDF pair is A' = f. Same with any running total vs its rate: cumulative loss whose slope is current loss, cumulative count whose slope is the instantaneous rate.

  • Treating the FTC as a coincidence. It follows from the sliver: extending area by dx adds f(x)·dx.
  • Forgetting the start point. A is measured from a fixed a; different starts differ by a constant (the +C).
  • Confusing the curve with its area function. f is the height (rate); A is the accumulated area (total).
  • Thinking area and slope are unrelated. The slope of the area function is the curve.

The slope of an accumulated area is the curve being accumulated, so integration and differentiation undo each other, which is the fundamental theorem.